Differential or U-tube Manometer

This is used to measure the pressure differential between two fluid reservoirs containing fluid with density rhoR, e.g. different pipes, or parts of the same pipe (we will cover this more in the Fluid Dynamics lesson) or two different vessels or parts of the same vessel.

The pressure gauge is constructed of a U-shaped transparent tube partially filled with high-density liquid of density ρₘ connecting two points at different pressures (see the figure below). The unknown pressure is indicated by the difference between the levels of liquid in the two arms of the U-tube.

Figure: A U-tube manometer containing fluid of density ρₘ connected between two reservoirs containing fluid of density ρR

Figure: A U-tube manometer containing fluid of density ρₘ connected between two reservoirs containing fluid of density ρR

The differential pressure is given directly as the head (or vertical interval) of the measuring fluid as:

P subscript 1 space minus space P subscript 2 space space equals space left parenthesis rho ₘ space minus space rho subscript R right parenthesis space g Z

If the reservoir fluid was a gas, then we could ignore its density term rho R, and the expression would reduce to:

P subscript 1 space minus space P subscript 2 space end subscript space equals space space rho ₘ g Z

Example:

A U-tube manometer is used to monitor the pressure across a compressed air filter. The U-tube is filled with liquid of a density 13,600 kg/m³, and the density of the air is 6 kg/m³. If the maximum pressure drop across the filter is to be limited to 0.5 bar, what would the vertical interval be on the U-tube manometer?

 Our equation for a U-tube manometer is:

P subscript 1 space end subscript minus space P subscript 2 space end subscript equals space left parenthesis rho ₘ space minus space rho subscript R right parenthesis space g Z

As we are after the vertical interval or distance Z on the manometer, we can rearrange this equation for Z:

Z space equals space fraction numerator P subscript 1 space end subscript minus space P subscript 2 over denominator left parenthesis rho ₘ space minus space rho subscript R right parenthesis space g end fraction

And substitute in the values that we know:

Z space equals space fraction numerator 50 comma 000 over denominator left parenthesis 13 comma 600 space minus space 6 right parenthesis space cross times space 9.81 end fraction space equals space 0.3749 space m

If we ignored the density of air from the calculation, the error would be:

Z space equals space fraction numerator 50 comma 000 space over denominator left parenthesis 13 comma 600 right parenthesis space cross times space 9.81 end fraction space equals space 0.3748 space m

With a less than 0.03% difference, we would be more than validated in ignoring the density of air to simplify such a calculation, in this case.

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