Using our Rearranged Equations to Calculate the Answer

We have, through our mathematical brilliance, produced the exact equation we need to find the answer that will guarantee exam success. Now it’s time to calculate the answer. As with all things mathematical, there are rules we need to follow to avoid getting it wrong.

Inputting the numbers for the terms and checking units

In all CIBD lessons, we see an equation and a list of numbers that correspond to the terms in the equation. While working through the calculation, it is important to check that the units agree. Let’s go through an example to help with this important point.

We are given the mass flow rate, represented by the symbol G, of a product being transferred from one vessel to another. We are asked to convert that mass flow rate into volumetric flow rate with units of cubic metres per second:

G space equals space 2 comma 000 space k g divided by h r

The equation to convert mass flow rate to volumetric flow rate is:

G space equals space rho Q

To isolate volumetric flow rate (Q), we rearrange the equation:

Q space equals G over rho

You will notice another term in this equation. The symbol ρ, pronounced ‘row’, represents fluid density and has units of mass per unit volume. For this example, the product being transferred has a density of 1,010 kg/m3. With this process information, we can proceed by adding these values to our equation:

Q space equals space fraction numerator 2 comma 000 begin display style fraction numerator k g over denominator h r end fraction end style over denominator 1 comma 010 space begin display style fraction numerator k g over denominator m cubed end fraction end style end fraction

Let’s look at the units for a moment:

Q space equals space fraction numerator begin display style fraction numerator k g over denominator h r end fraction end style over denominator begin display style fraction numerator k g over denominator m cubed end fraction end style end fraction

Remembering the unit cancellation techniques we used earlier, we can rearrange this to:

Q space equals space fraction numerator horizontal strike k g end strike over denominator h r end fraction space cross times space fraction numerator m cubed over denominator horizontal strike k g end strike end fraction

Then cancel the kg to get:

Q space equals space fraction numerator m cubed over denominator h r end fraction

As this is volume per unit time, it confirms that we properly performed this calculation. Given this, we then can complete the calculation:

Q space equals space fraction numerator 2 comma 000 begin display style fraction numerator k g over denominator h r end fraction end style over denominator 1 comma 010 space begin display style fraction numerator k g over denominator m cubed end fraction end style end fraction space equals space 1.980 space fraction numerator m cubed over denominator h r end fraction

Terrific. We have a volumetric flow rate! One thing remains – converting the rate from hours to seconds. As there are 60 seconds in a minute and 60 minutes in an hour, then 60 × 60 = 3,600 seconds in an hour:

Q space equals space 1.980 space fraction numerator m cubed over denominator h r end fraction space cross times space fraction numerator 1 space h r over denominator 3 comma 600 space s end fraction space equals space 0.00055 space m cubed over s

As before, the hrs cancel, and we are left with the volumetric flow rate in m3/s.

And to consolidate what we know, we can tackle a problem from a topic we will master in Module 3. The equation below can be rearranged and used to calculate the area (A) of a heat transfer surface:

q space equals space A h space left parenthesis T subscript w space end subscript minus space T subscript infinity right parenthesis

For this question, here are the values you will need:

q equals space 1 comma 413 comma 000 space 𝑊 space space
h space equals space 1 comma 200 space W. space m to the power of negative 2 end exponent space K to the power of negative 1 end exponent
T subscript w space equals space 130 space K space space
T subscript infinity space equals space 100 space K

We don’t need to know what the other terms relate to here because we are only interested in the techniques.

The first thing we will need to do is rearrange the equation to isolate A. This is nice and easy as A is being multiplied so, we just divide both sides by everything that is multiplying it:

A space equals space fraction numerator q over denominator h space left parenthesis T subscript w minus T subscript infinity right parenthesis end fraction

Insert the provided values and units for each term. Notice that we need to convert the W. space m to the power of negative 2 end exponent space K to the power of negative 1 end exponent into the fraction form of this unit:

A space equals space fraction numerator 1 comma 413 comma 000 space W over denominator 1 comma 200 space begin display style fraction numerator W over denominator m squared K end fraction end style space cross times space left parenthesis 130 minus 100 right parenthesis space K end fraction

Let’s check our units by using the cancellation techniques we have already learned:

fraction numerator W over denominator begin display style fraction numerator W over denominator m squared K end fraction end style space cross times space K end fraction

First, we make K a fraction with 1 as the denominator:

fraction numerator W over denominator begin display style fraction numerator W over denominator m squared K end fraction end style space cross times begin display style fraction numerator space K over denominator 1 end fraction end style end fraction

Next, start cancelling out units:

fraction numerator W over denominator begin display style fraction numerator W over denominator m squared horizontal strike K end fraction end style space cross times begin display style fraction numerator space horizontal strike K over denominator 1 end fraction end style end fraction

This leaves:

fraction numerator W over denominator begin display style W over m squared end style space cross times begin display style fraction numerator space 1 over denominator 1 end fraction end style end fraction

And becomes:

fraction numerator W over denominator begin display style W over m squared end style end fraction

To cancel the Watts, we can rearrange to change this from one fraction divided by another to one fraction multiplied by the reciprocal of the other. Like so:

fraction numerator horizontal strike W over denominator 1 end fraction space cross times space space fraction numerator m squared over denominator horizontal strike W end fraction

 Leaving:

m squared

With a sensible final unit of measurement confirmed, we calculate the answer following the PEMDAS order of operation:

A space equals space fraction numerator 1 comma 413 comma 000 space W over denominator 1 comma 200 space begin display style fraction numerator W over denominator m squared K end fraction end style space cross times space left parenthesis 130 space minus space 100 right parenthesis space K end fraction

First parenthesis:

A space equals space fraction numerator 1 comma 413 comma 000 space W over denominator 1 comma 200 space begin display style fraction numerator W over denominator m squared K end fraction end style space cross times space left parenthesis 30 right parenthesis space K end fraction

Then multiplication and division:

A space equals space fraction numerator 1 comma 413 comma 000 space W over denominator 36 comma 000 space begin display style W over m squared end style space end fraction

A equals space 39.25 space m squared

Then we verify that our units of measurement are correct. After all of the cancellations are complete, we are left with m2, which is an appropriate unit for the area. This provides a sense of validation that we understood the question, used the proper equation, and input the right values. Because of this, it is quite likely that our answer is correct.

To help reinforce what we have just learned, on the next page there are some practice questions. Answers and explanations can be revealed by clicking on show answer.

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