Steam Tables

Steam tables are most commonly used to retrieve thermodynamic data for water when operating conditions have been specified.

Steam table information is commonly provided in even increments, based on a given saturation temperature or saturation pressure. There are also tables for superheated steam and for compressed water. The steam table below provides thermodynamic data for saturated water and saturated steam. One downside of steam tables is that, if we want a temperature or pressure between these increments, then we need to interpolate between the two closest figures – or find a chart with smaller or different increments!

Table: Steam table

Temperature

°C

Pressure

MPa

Specific Volume

m cubed space k g to the power of negative 1 end exponent

Specific Enthalpy

Liquid

k J space k g to the power of negative 1 end exponent

Specific Enthalpy of Vaporisation

k J space k g to the power of negative 1 end exponent

Specific Enthalpy Vapour

k J space k g space to the power of negative 1 end exponent

0.01

0.000612

205.9912

0

2,500.92

2,500.92

5

0.000873

147.0113

21.02

2,489.04

2,510.06

10

0.001228

106.3

42.02

2,477.19

2,519.21

30

0.004247

32.8783

125.73

2,429.82

2,555.55

50

0.012400

12.0269

209.34

2,381.95

2,591.29

70

0.031200

5.0395

293.07

2,333.03

2,626.10

90

0.070200

2.3591

377.04

2,282.49

2,659.53

100

0.101400

1.6718

419.17

2,256.40

2,675.57

125

0.232200

0.7700

525.07

2,188.03

2,713.10

150

0.476200

0.3925

632.18

2,113.75

2,745.93

179.88

1

0.1944

762.52

2,014.59

2,777.11

200

1.55490

0.1272

852.27

1,939.74

2,792.01

225

2.54970

0.0784

966.80

1,835.35

2,802.15

263.94

5

0.0394

1,154.64

1,639.57

2,794.21

280

6.41660

0.0302

1,236.88

1,542.99

2,779.87

285.83

7

0.0274

1,267.66

1,504.97

2,772.63

295.01

8

0.0235

1,317.31

1,441.37

2,758.68

311.00

10

0.0180

1,408.06

1,317.43

2,725.49

 

The column titled ‘Specific Volume’ refers to the volume occupied by 1 kg of steam at a given pressure and temperature. It is useful to know this when sizing steam pipework systems in the brewery.

It is important to note that the above steam tables (and many Mollier diagrams) are in absolute pressure. However, many pressure readings in a brewery will be gauge pressure. Absolute pressure is the pressure which includes atmospheric pressure, while gauge pressure is relative to atmospheric pressure.

P subscript a b s end subscript equals P subscript g plus P subscript a t m end subscript

Where Patm  is atmospheric pressure, which at sea level is 101.325 kPa (0.101 MPa).

Data from steam tables is often used to calculate heat loads in water and steam systems. Let’s look at an example of this now.

What is the total amount of steam and the flow rate required when heating a hot water tank containing 100 hL (10,000 kg) of water from 10°C to 90°C in 30 minutes? Steam is available at 5 MPa (4.9 MPa g). The steam data is available in the steam table above. The specific heat capacity of water is 4.184 kJ kg-1 K-1.

To answer this, we need to set up an energy balance to say that the amount of energy from the steam is equal to the amount of energy needed to increase the temperature of water from 10°C to 90°C. This is valid if we assume that there is no heat loss to the surrounding environment.

The energy required to change the temperature of water is the sensible heat. Remember, the sensible heat is calculated as:

Q equals M C increment T

Q equals left parenthesis 10 comma 000 right parenthesis space cross times space left parenthesis 4.184 right parenthesis space cross times space left parenthesis 90 minus 10 right parenthesis equals 3 comma 347 comma 200 space k J

Now, we need to determine how much 5 MPa steam we need. The energy available per kg of steam is the enthalpy of vaporisation (taken from the steam table). At 5 MPa, the enthalpy of vaporisation is 1,639.57 kJ kg-1. Therefore, total energy of steam would be calculated as:

Q equals M increment H subscript v a p end subscript

We can equate this to the energy required to heat the water and use it to finally solve for M.

3 comma 347 comma 200 equals M left parenthesis 1 comma 639.57 right parenthesis

M equals 2 comma 041.5 space k g

To calculate the steam flow rate, we divide the total steam by the time, and arrive at m.

m equals M over t equals fraction numerator 2 comma 041.5 space k g over denominator 0.5 h r end fraction equals 4 comma 083 space k g space h r to the power of negative 1 end exponent

So far, we have covered the fundamental concepts of steam and we have learned how to calculate a steam mass flow rate for a required brewery operation. Now that we understand these concepts, we can discuss the different types of steam and identify the ideal steam for brewery use.

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