Rearranging Equations – Dealing with Fractions

When we say fractions, we are not just talking about halves or quarters etc., we mean terms made of numerators and denominators. Let’s find out more.

The inverse operation of multiplying by a fraction is multiplying by the opposite fraction. The opposite fraction is called its reciprocal. You can check this works by following this calculation:

12 space cross times space 3 over 4 space equals space 9

9 space cross times space 4 over 3 space equals 12

The same applies for dividing by fractions:

fraction numerator 12 over denominator begin display style bevelled 3 over 4 end style end fraction space equals space 12 space cross times space 4 over 3 space equals 16

fraction numerator 16 over denominator begin display style bevelled 4 over 3 end style end fraction space equals space 16 space cross times space 3 over 4 space equals 12

For example, in this equation from a heat transfer lesson:

t fraction numerator A U over denominator M C p end fraction space equals space open square brackets l n fraction numerator T subscript s space minus space T subscript 1 over denominator T subscript s space minus space T subscript 2 end fraction close square brackets

We can isolate t by multiplying both sides by the reciprocal of fraction numerator A U over denominator M C p end fraction which is fraction numerator M C p over denominator A U end fraction. This cancels out the fraction numerator A U over denominator M C p end fraction on the left to give us:

t space equals space open square brackets l n fraction numerator T subscript s italic space italic minus T subscript italic 1 italic space over denominator T subscript s italic minus italic space T subscript italic 2 end fraction close square brackets space open square brackets fraction numerator M C p over denominator A U end fraction close square brackets

But what if the term we need to isolate is part of a fraction? Say we need to know what A is in this equation:

t fraction numerator A U over denominator M C p end fraction bold space equals space open square brackets italic ln fraction numerator T subscript s italic space italic minus italic space T subscript italic 1 over denominator T subscript s space italic minus italic space T subscript italic 2 end fraction close square brackets

First, we can do an inverse operation to move the rest of the fraction, so multiply both sides by fraction numerator M C p over denominator U end fraction cancelling out the fraction numerator U over denominator M C p end fraction on the left and giving us:

t A space equals bold space open square brackets l n fraction numerator T subscript s italic space italic minus italic space T subscript italic 1 over denominator T subscript s space italic minus italic space T subscript italic 2 end fraction close square brackets bold space open square brackets fraction numerator M C p over denominator space U end fraction close square brackets

Then to isolate A, we just need to divide both sides by t to give us:

A space equals bold space fraction numerator open square brackets italic ln fraction numerator T subscript s italic space italic minus italic space T subscript italic 1 over denominator T subscript s space italic minus italic space T subscript italic 2 end fraction close square brackets bold space open square brackets begin display style fraction numerator M C p over denominator U end fraction end style close square brackets over denominator t end fraction

Troublesome numerators

What if you need to isolate a term in a bracket in the numerator of a fraction? Let’s say we need to isolate rho subscript straight p in the equation for Stoke’s law (shown below):

nu space equals space 2 over 9 fraction numerator left parenthesis rho subscript p space minus space rho subscript f right parenthesis space over denominator mu end fraction space g space R squared

A numerator’s job is to be divided by a denominator. As the numerator is the subject of an action and not performing an action on another term, it isn’t actually doing anything, so we can’t undertake an inverse operation on it. We therefore need to undertake an inverse operation on all the other terms on the same side of the equation. See what we mean about troublesome numerators!

We can start by dividing both sides by g R2  to get:

fraction numerator nu space over denominator g space R squared end fraction equals space 2 over 9 fraction numerator left parenthesis rho subscript p space minus space rho subscript f right parenthesis space over denominator mu end fraction space

We now have a fraction multiplying what we need to isolate so we can multiply both sides by its reciprocal 9 over 2 to move it across the equals sign and get:

fraction numerator nu space over denominator g space R squared end fraction space 9 over 2 space equals space fraction numerator left parenthesis rho subscript p space minus space rho subscript f right parenthesis space over denominator mu end fraction space

And now we can multiply both sides by mu to get:

fraction numerator nu space over denominator g space R squared end fraction space 9 over 2 space mu equals space rho subscript p space minus rho subscript f space

 And finally add rho subscript f to both sides to get:

rho subscript p space equals space open parentheses fraction numerator nu space over denominator g space R squared end fraction space 9 over 2 close parentheses space mu space plus space rho subscript f

To help reinforce what we have just learned, on the next page there are some practice questions. Answers and explanations can be revealed by clicking on show answer.

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