Dalton’s Law and Partial Pressures

Perhaps unknowingly, we have already defined above, the concept of partial pressure.

A partial pressure is the pressure which a single gas would exert if it alone occupied the volume of a mixture.

In the previous example, at a mixture pressure of 10 bar a, the partial pressures of CO2 and N2 would be 2 and 8 bar a, respectively. We can apply our universal gas law to this situation, namely, defining the partial pressures of 2 and 8 bar a for the CO2 and N2 gas mixture in a vessel of volume V and at temperature T.

The partial pressure of CO2 pCO2 is given by:

p subscript C O subscript 2 end subscript space equals space fraction numerator n subscript C O subscript 2 end subscript R T over denominator V end fraction space equals space 2 space b a r space a

The partial pressure for N2:

p subscript N subscript 2 end subscript space equals space fraction numerator n subscript N subscript 2 end subscript R T over denominator V end fraction space equals space 8 space b a r space a

The mixture to give the mixture pressure PT:

P subscript T space equals space fraction numerator left parenthesis n subscript N subscript 2 end subscript space plus space n subscript C O subscript 2 end subscript right parenthesis space R T over denominator V end fraction space equals space fraction numerator n subscript T R T over denominator V end fraction space equals space 10 space b a r space a

Where nT is the total number of moles of CO2 and N2.

So, if we take the ratio of the partial pressure of CO2 to the mixture pressure PT:

p subscript C O subscript 2 end subscript over P subscript T space equals space fraction numerator begin display style fraction numerator n subscript C O subscript 2 end subscript R T over denominator V end fraction end style over denominator begin display style fraction numerator n subscript T R T over denominator V end fraction end style end fraction space equals space space n subscript C O subscript 2 end subscript over n subscript T

Rearranging for the partial pressure of CO2:

p subscript C O subscript 2 end subscript space equals space P subscript T space n subscript C O subscript 2 end subscript over n subscript T

A similar expression can be derived for the partial pressure of nitrogen:

p subscript N subscript 2 end subscript space equals space P subscript T space n subscript N subscript 2 end subscript over n subscript T

The ratio of the number of moles of either gas to the total number of moles of gas, i.e. nCO2/nT or nN2/nT is known as the molar fraction. Another way to think of this is the fraction of any individual gas component to the total number of moles of the mixture. We commonly give the molar fraction the symbol x:

p subscript C O subscript 2 end subscript space equals space P subscript T x subscript C O subscript 2 end subscript

p subscript N subscript 2 end subscript space equals space P subscript T x subscript N subscript 2 end subscript

If we summed both partial pressures, we would get the total mixture pressure PT:

P subscript T space equals space p subscript C O subscript 2 end subscript space plus space p subscript N subscript 2 end subscript space equals space P subscript T x subscript C O subscript 2 end subscript space plus space P subscript T x subscript N subscript 2 end subscript

P subscript T space equals space P subscript T space left parenthesis x subscript C O subscript 2 end subscript space plus space x subscript N subscript 2 end subscript right parenthesis

We can show that the sum of the molar fractions is one:

x subscript C O subscript 2 space end subscript plus space x subscript N subscript 2 end subscript space equals space 1

Dalton’s law states that in a non-reactive gas mixture, the total pressure of a mixture of gases is the sum of the individual partial pressures of the gases in the mixture at constant volume and temperature.

John Dalton (1766-1844) was an English chemist, physicist and meteorologist who made major contributions in chemistry, physics, and many other fields, including mountaineering. He was considered an authority in the heights of local mountains which he used to climb to take atmospheric readings from the summit. From these readings, he would estimate the height using the change in atmospheric pressure from the foot of the mountain to its summit.

You have completed 0% of the lesson
0%