Suggested Response - Q3

* Calculate the heat transfer rate due to convection in a pipe between water flowing within it at 90°C and the inside of the pipe wall at 10°C.  The length of the pipe is 6.5 m with an inner diameter of 0.5 m. The film heat transfer coefficient is 1,020 W m-2 K-1.

Response: 

To calculate the heat transfer rate due to convection, we will use Fourier’s law:

q space equals space h A left parenthesis T subscript w space minus space T subscript infinity right parenthesis

Where

q is the rate of heat flow, measured in J s-1 (W)

A is the surface area, measured in m2

h is the film heat transfer coefficient in Wm-2 K-1

Tw is the temperature of wall or pipe, measured in K

T∞  is the bulk temperature of the fluid past the thermal boundary layer, measured in K

We first need to calculate the surface area for heat transfer via convection. The surface area of a pipe is as follows:

A space equals space 2 pi r L

A space equals space 2 space cross times space pi space cross times space 0.25 space cross times space 6.5

A space equals space 10.2 space m squared

The rest are given in the problem statement, and therefore we can simply enter them and calculate.

q space equals space h A left parenthesis T subscript w space minus space T subscript infinity right parenthesis

q space equals space 1 comma 020 space cross times space 10.2 space cross times space left parenthesis 10 space minus space 90 right parenthesis

Note: although we have defined Tw and T∞ in Kelvin, as any temperature in centigrade is the temperature in Kelvin minus 273, (Tw - T∞) has the same value in both units. We therefore don’t need to convert centigrade into Kelvin for this calculation.

q space equals space minus 832 comma 320 space W space equals space minus 832 space k W

Note that the value calculated here is a negative number. This is because the heat is being removed from the hot water.

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